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Inhaltsangabe
This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1900 Excerpt: ...45. (1397) Head-41-h.434 = 94.47 ft. Using formula 172,-Z 00 X COX?. 48 X. 087267 ( 1 399) (a) Area of pump-piston = (£) x. 7854 =. 19635 sq. in. Area of plunger = 10s X.7854 = 78.54 sq. in. 100 Pressure per sq. in. exerted by piston = pounds.,190o5 Hence, according to Pascal's law, the pressure on the plunger is--У;г X 78.54 = 40,000 Ib. Ans.. Uuoo (b) According to the principle given in Art. 2181, D X 14-inches = W X distance moved by plunger, or 100 X 1£ = 40,000 X required distance; hence, the required dis.0205--.0193 =.0012. X 3.5 =.00105, or say.0011. 4.0205-.0011 =.011)4=/ for vm = 11.5. Ans. (1406) The specific gravity of sea-water is 1.026 (see table of Specific Gravity); hence, the weight of a cubic foot of sea-water = 1.026 X 62.5 = 64.1 Ib. 10 V v (1 Total area of cube =--sq. ft. 1 mile = 5,280 ft. Hence, total pressure on cube =--'---r--X 5,280 X 3.5 X 64.1 = 5,441,609.25 Ib. Ans. (1407) (¿) The pressure per square inch equals the weight of a volume of water 1 in. square and 12 in. high; that is, it equals 1 X 1 X.03617 X 12 =.434 Ib., nearly. Ans. (a) Total pressure on the bottom = area of bottom in square inches multiplied by the pressure per square inch = 8 X.7854 X.434=21.82 Ib. Ans.-= 5.535 у. = Ц in. Ans. fcj 70 (1409) See Art. 2266. (1410) The height to which a pump will lift water is directly proportional to the atmospheric pressure; that is, proportional to the length of the mercury column. Letting x represent the height to which the pump will iift the water on top of the mountain, we have the proportion, 30: 22:: 25.5: x, or 30x = 22 X 25.5; whence, x = 18.7 ft. Ans. (1411) Area of dam = 40 X 12 = 480 sq. ft. X 12 = 6 ft., depth of center of gravity below the level «f" the liquid. The t...
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This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1900 Excerpt: ...45. (1397) Head-41-h.434 = 94.47 ft. Using formula 172,-Z 00 X COX?. 48 X. 087267 ( 1 399) (a) Area of pump-piston = (£) x. 7854 =. 19635 sq. in. Area of plunger = 10s X.7854 = 78.54 sq. in. 100 Pressure per sq. in. exerted by piston = pounds.,190o5 Hence, according to Pascal's law, the pressure on the plunger is--У;г X 78.54 = 40,000 Ib. Ans.. Uuoo (b) According to the principle given in Art. 2181, D X 14-inches = W X distance moved by plunger, or 100 X 1£ = 40,000 X required distance; hence, the required dis.0205--.0193 =.0012. X 3.5 =.00105, or say.0011. 4.0205-.0011 =.011)4=/ for vm = 11.5. Ans. (1406) The specific gravity of sea-water is 1.026 (see table of Specific Gravity); hence, the weight of a cubic foot of sea-water = 1.026 X 62.5 = 64.1 Ib. 10 V v (1 Total area of cube =--sq. ft. 1 mile = 5,280 ft. Hence, total pressure on cube =--'---r--X 5,280 X 3.5 X 64.1 = 5,441,609.25 Ib. Ans. (1407) (¿) The pressure per square inch equals the weight of a volume of water 1 in. square and 12 in. high; that is, it equals 1 X 1 X.03617 X 12 =.434 Ib., nearly. Ans. (a) Total pressure on the bottom = area of bottom in square inches multiplied by the pressure per square inch = 8 X.7854 X.434=21.82 Ib. Ans.-= 5.535 у. = Ц in. Ans. fcj 70 (1409) See Art. 2266. (1410) The height to which a pump will lift water is directly proportional to the atmospheric pressure; that is, proportional to the length of the mercury column. Letting x represent the height to which the pump will iift the water on top of the mountain, we have the proportion, 30: 22:: 25.5: x, or 30x = 22 X 25.5; whence, x = 18.7 ft. Ans. (1411) Area of dam = 40 X 12 = 480 sq. ft. X 12 = 6 ft., depth of center of gravity below the level «f" the liquid. The t...
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